Calculate the de-Broglie wavelength for electron moving with speed of `6 xx 10^5 m s^(-1)`.

Explanation

`v=6 xx 10^(5) m//s`
`h= 6.62 xx 10^(-34) Js`
`m_(e)= 9.1 xx 10^(-31)kg`
de-Broglie wavelength of an electron `=lamda_(e)`= ?
`lamda_(e)= (h)/(m_(e )v)= (6.62 xx 10^(-34))/(9.1 xx 10^(-31) xx 6 xx 10^(5))`
`lamda_(e)= 0.121 xx 10^(-8)m`
`lamda_(e)= 1.21 xx 10^(-9)m`
`lamda_(e )= 1.21nm`