Calculate the de-Broglie wavelength of an electron moving with a speed of `9 xx 10^(5) m//s`. Given `h= 6.6 xx 10^(-34)Js` and mass of electron `=9.1 xx 10^(-31) kg`.

Explanation

`lamda_(e)`= ? `v=9 xx 10^(5)m//s, h=6.6 xx 10^(-34) Js, m_(e)= 9.1 xx 10^(-31)kg`
`lamda_(e)= (h)/(m_(e)v)= (6.6 xx 10^(-34))/(9.1 xx 10^(-31) xx 9xx 10^(5))`
`lamda_(e)= 0.08058 xx 10^(-8)m`
`lamda_(e)= 8.058 xx 10^(-10)m= 8.1 Å`