What is the de-Broglie wavelength of an electron beam accelerated through a potential difference of 25 V?

Explanation

V=25V De-broglie wavelength =`lamda`=? `lamda= (12.27)/(sqrtV) Å`
`lamda= (12.27)/(sqrt25)Å`
`lamda = (12.27)/(5) Å`
`lamda= 2.454 Å`