If 200 MeV energy is produced for a single fission of `""_(92)U^(235)`, how many fissions must take place per hour to produce a power of `10^(3)` KW ?

Explanation

`P = 10^(3)KW = 10^(3) xx 10^(3)W`
`P = 10^(6) Js^(-1)`
`P = 10^(6) xx 3600 J "hour"^(-1)`
`= 36 xx 10^(8) "J hour"^(-1)`
Total energy produced in 1 hour `= 36 xx 10^(8)J`
Energy released in single fission = 200 MeV
`= 200 xx 1.6 xx 10^(-13)`
`= 3.2 xx 10^(-11)J`
Number of fissions taking place per hour `= ("Total energy")/("Energy released in single fission")`
`= (36 xx 10^(8))/(3.2 xx 10^(-11))`
`= 11.25 xx 10^(19)`
`= 1.125 xx 10^(20)` fission/hour