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If every fission of ""(92)U^(235) releas...

If every fission of `""_(92)U^(235)` releases 200.8 MeV energy, then find the rate of fission, if a total power 2 MW is released.

Text Solution

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Power = P = 2 MW
`= 2 xx 10^(6)W`
`P = 2 xx 10^(6)J//s`
Total enery released per second `= 2 xx 10^(6)J//s`
Energy relesed per fission = 200.8 MeV
`= 200.8 xx 1.6 xx 10^(-3)`
`= 3.128 xx 10^(-11)J`
Rate of fission `= ("Total energy")/("Energy released per fission")`
`= (2 xx 10^(6))/(3.2128 xx 10^(-11))`
`= 0.6225 xx 10^(17)`
`= 6.23 xx 10^(16)` fissions/s
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