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If every fission of ""(92)U^(235) releas...

If every fission of `""_(92)U^(235)` releases 200 MeV energy, then find the rate of fission, if a total power 3 MW is released.

Text Solution

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Power = P = 3 MW
`= 3 xx 10^(6)W`
`P = 3 xx 10^(6)J//s`
Energy released per fission = 200 MeV
`= 200 xx 1.6 xx 10^(-13) J`
`= 3.2 xx 10^(-11) J`
Total energy released per second `= 3 xx 10^(6)J`
Rate of fission `= ("Total energy")/("Energy released per fission")`
`= (3 xx 10^(6))/(3.2 xx 10^(-11))`
`= 0.9375 xx 10^(17)`
`= 9.38 xx 10^(16)` fissions.
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