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If every fission of ""(92)U^(235) releas...

If every fission of `""_(92)U^(235)` releases 200.8 MeV energy, then find the rate of fission, if a total power 2 MW is released.

Text Solution

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Power = P = 2 MW
`= 2 xx 10^(6)W`
`= 2 xx 10^(6) J//s`
Energy released per fission = 200.5 MeV
`= 200.5 xx 1.6 xx 10^(-13)J`
`= 320.8 xx 10^(-13)J`
`= 3.208 xx 10^(-1)J`
Total energy released per second `= 2 xx 10^(6)J//s`
Rate of fission `= ("Total energy")/("Energy released per fission")`
`= (2 xx 10^(6))/(3.208 xx 10^(-11))`
`= 0.623 xx 10^(17)`
`= 6.23 xx 10^(16)` fissions/s
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