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A semiconductor has accpetor level 1.57 ...

A semiconductor has accpetor level 1.57 eV above the valence band.What is the maximum wavelength of light required to create a hole?Given that `1 eV=1.6 xx 10^(-19)J` and `h=6.62 xx 10^(-34) Js`.

Text Solution

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Energy `=E_(g)= 57MeV`
`E_(g)= 57 xx 1.6 xx 10^(-19) xx 10^(-3)J`
Planck.s constant `=h= 6.62 xx 10^(-34) Js`
Wavelength of light= ? `E= (hc)/(lamda)`
`lamda= (hc)/(E )`
`= (6.62 xx 10^(-34) xx 3 xx 10^(8))/(57 xx 1.6 xx 10^(-19) xx 10^(-3))`
`=0.2178 xx 10^(-4)`
`=2.178 xx 10^(-5)m`
`lamda= 2.178 xx 10^(-5)m`
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