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The energy liberated in the ecombinatio...

The energy liberated in the ecombination of hole-electron pair is converted into electromagnetic radiation. If the maximum wavelength emitted is 500 nm, find value of forbidden energy gap.

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`lamda= 500nm= 500 xx 10^(-9) m= 5 xx 10^(-7)m`
`h= 6.62 xx 10^(-34)Js, c= 3 xx 10^(8) ms^(-1)`
`E_(g)= (hc)/(lamda)= (6.62 xx 10^(-34) xx 3 xx 10^(8))/(5 xx 10^(-7))`
`E_(g)= (19.86)/(5) xx 10^(-19)J`
`=3.972 xx 10^(-11)`
`=(3.972 xx 10^(-19))/(1.6 xx 10^(-9))eV`
`E_(g)= 2.48 eV`
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