A transistor connected in cdmmon emitter configuration has input resistance `Ri = 2k Omega` (kilo ohm) and load resistance `6k Omega` (kilo ohm). If current gain `beta = 60` and input signal 10 mV (millivolt) is applied, calculate resistance gain

Explanation

`R_(i)=2k Omega= 2000Omega`
`R_(L)= 6k Omega= 6000Omega`
`beta= 60`
`V_(i)= 10mV= 10 xx 10^(-3)V= 10^(-2)` volt
Resistance gain `=(R_(L))/(R_(i))= (6000)/(2000)=3`
Voltage gain `=A_(v)= beta xx (R_(L))/(R_(i))`
`A_(v)= 60 xx (6000)/(2000)=180`
Power gain `=A_(v) xx beta`
`=180 xx 60`
=10800