Home
Class 12
PHYSICS
In a diode detector output circuit ...

In a diode detector output circuit consist of R =1 `M Omega` and C = 1 pF, calculate the carrier frequency it can detect.

Text Solution

Verified by Experts

Resistance ` = R =1 M Omega = 10^(6) Omega`
Capacitance ` = C = 1 pF = 1 xx 10^(-12) F`
`RC = 10^(6) xx 10^(-12) = 10^(-6) S `
Let `f_(c)` = Carrier frequency
` (1)/(f_(c)) lt lt ` RC for good detection of signal .
`rArr " " f_(c) gt gt (1)/(RC)`
` f_(c) gt gt (1)/(10^(-6))`
`f_(c) gt gt 10^(6) Hz`
or `f_(c) gt gt 1 MHz` .
Promotional Banner

Topper's Solved these Questions

  • PRINCIPLES OF COMMUNICATION

    BETTER CHOICE PUBLICATION|Exercise SHORT ANSWER TYPE QUESTIONS|42 Videos

  • POLARISATION OF LIGHT

    BETTER CHOICE PUBLICATION|Exercise Most Expected Questions|4 Videos

  • RADIOACTIVITY

    BETTER CHOICE PUBLICATION|Exercise MOST EXPECTED QUESTIONS |6 Videos

Similar Questions

Explore conceptually related problems

In a diode detector, output circuit consists of a resistor of 10MOmega and a capacitor of 1pF.Calculate the carrier frequency it can detect.

A 200 V varialbe frequency a.c. source is connected to a series combination the L= 5H , C = 80 mu F and R = 40 Omega . Calculate the angular frequency of the soucre to get maximum current in the cicuit, the current amplitude at resonance and power dissipated in the circuit.

An LCR circuit has L = 10 mH, R = 3 Omega and C = 1 mu F and is connected in series to a source of (15 cos omega t) volt. Calculate the current amplitude at a frequency 10 % lower than the resonance frequency of the circuit.

A series LCR circuit with R= 20 Omega ,L=1.5H and C = 35 muF is connected to a variable-frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit, what is the average power transferred to the circuit in one complete cycle?