Silver forms cpp lattice and X-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate density of silver (Atomic mass 107.9 n).

Explanation

`a=408.6"pm"=408.6xx10^(-10)cm`
`=4.086xx10^(-8)cm`
`z=4,M=1079"g mol"^(-1)`
`N_(A)=6.022xx10^(23)"mol"^(-1),d=?` (for c.c.p. lattice)
`d=(zxxM)/(a^(3)xxN_(A))`
`d=(4xx107.9)/((408.6xx10^(-10))^(3)xx6.022xx10^(23))`
`=431.6/(40.899)`
= 10.7