An element having a density `11.2"g cm"^(-3)` forms a fcc lattice with edge of `4xx10^(-3)` cm. Calculate the atomic mass of the element.

An element with density 10 g cm^(-3) forms a cubic unit cell with edge length of 3xx10^(-8) cm.What is the nature of the cubic unit cell if the atomic mass of the element is 81 g mol^(-1)

An element has density 6xx8"g cm"^(-3) occurs in bcc structure with cell edge of 290 pm. Calculate the number of atoms present in 200 g of the element.

An element E crystallizes in boyd centred cubic structure. If the edge lengh of the cell is 1.469xx10^-10m and the denstiy is 19.3 g cm^-3 , calculate the atomic mass of this element. Also calculate the radius of an atom of the element.

An element crystallising in body centred cubic lattice has an edge length of 500 pm. If its density is 4gcm^-3 , the atomic mass of the element is

An element crystallises in a structure having fcc unit cell of edge length 200 pm. Calculate the density if 200 gm of this element contain 24xx10^(23) atoms.

The unit of an element of atomic mass 96 and density 10.3gcm^-3 is a cube with edge length of 314 pm. Find the structure of the crystal lattice (simple cubic, FCC or BCC) (Avagadro's constant, N_0=6.023xx10^23 mol^-1 ).

Density of a unit cell is respresented as rho = (" Effective no. of atoms (s)" xx "Mass of a unit cell ")/("Volume of a unit cell ")=(Z.M)/(N_(A).a^(3)) where , mass of unit cell =mass of effectuive no . of atoms(s) or ion (s). M= At . mass// formula N_(A) = Avogadro' s no . rArr 6.0323 xx 10^(23) a= edge lemght of unit cell An element crystallizes in a structure having fcc unit cell of an edge 200 pm . Calculate the density , if 100 g of this element contains 12xx10^(23) atoms :