A solid has NaCl structure. If the radius of cation A is 100 pm. What is the radius of anion B ?

Explanation

For NaCl type structure radius ratio `(r^(+)//r^(-))` lies between `0.414ler^(+)/(r^(-))le0.732`
here `r^(+)(A^(+))=100"pm"`
`0.414le(100"pm")/(r^(-))le0.732`
or `1/(0.414)ger^(-)/(100"pm")ge1/(0.732)`
`(100"pm")/(0.414)ger^(-)(B^(-))(100"pm")/(0.732)`
`rArr241.55"pm"ger^(-)(B^(-))ge136.61"pm"`
Therefore, radius of anion, `B^(-)` lies between 136.61 and 241.55 pm