The electrical resistance of a column of 0.05 mol `L^(-1)` NaOH solution of diameter 1 cm and length 50 cm is `5.55 xx 10^3` ohm. Calculate its resistivity, conductivity and molar conductivity.

Explanation

Step I : To calculate K
`R=rho(l)/(A)=(1)/(k)(l)/(A)`
`kappa=(l)/(RxxA)=(l)/(Rxxpir^(2))`
`r=d//2=1//2=0.5cm`,
`l=50cm,R=5.55xx10^(3)Omega`
`kappa=(50cm)/((5.55xx10^(3)Omega)xx3.142xx(0.5)^(2)cm^(2))`
`kappa=(50xx10^(-3)Omega^(-1)cm^(-1))/(5.55xx3.142xx0.25)`
`=(20xx10^(-2))/(5.55xx3.142)Omega^(-1)cm^(-1)`
`=1.1469xx10^(-2)Omega^(-1)cm^(-1)`