Calculate `DeltaG^(@)` for the following cell:
`Fe|Fe^(2+)||Cu^(2+)|Cu`.
Given that: `E^(@)(Cu^(2+)//Cu)=+0*34V,E^(@)(Fe^(2+)//Fe)=-0*44V.

Explanation

Step I. To calculate `EMF^(@)` and n cell is,
`Fe|Fe^(2+)||Cu^(2+)|Cu`
The cell reactions are,
Oxidation: `Fe(s) to Fe^(2+)(aq)+Cu(s)`
Reduction : `Cu^(2+)(aq)+2e^(-) to Cu(s)`
Overall: `Fe(s)+Cu^(2+)(aq)toFe^(2+)(aq)+Cu(s)`
Thus, n=2
`EMF^(@)=E^(@)(Cu^(2+)//Cu)-E^(@)(Fe^(2+)//Fe)`
`=0*34V-(-0*44V)`
`=0*78V`