A 0.05 M NaOH solution offered a resistance of 31.6 ohm ina conductivity cell at 298 K. if the area of the plates of the conductivity cell is 3.8 `cm^2 ` and distance between them 1.4 cm. calculate the molar conductivity of the NaOH solution.

Explanation

To calculate `kappa`
`kappa=(1)/(R)xx(l)/(a)`
Here `R=31*6Omega,1=I*4cm,a=3*8cm^(2)`
`therefore kappa=(1)/(31*6Omega)xx(1*4cm)/(3*8cm^(2))`
`=1*1659xx10^(-2)Omega^(-1)cm^(-1)`