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Write Nernst equation and calculate the e.m.f. of the following cell at 298 K:
`Cu(s)|Cu^(2+)(0.130M)||Ag^(+)(1.0xx10^(-4)M)|Ag(s)`
Given that: `E_(Cu^(2+)//Cu)^(@)=+0.34V and E_(Ag^(+)//Ag)^(@)=+0.80V`
(log 0.130=-1.1139).

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