What mass of zinc can be produced by the electrolysis of zinc sulphate solution when a current of 1.5 amperes is passed for 15 minutes ? The atomic mass of zinc=65.4 amu.

Explanation

`I=1.5A,t=15" min"=15xx60s=900s`
`Q=Ixxt=(1.5A)xx(900s)=1350C`
`ZnSO_(4)hArr Zn^(2+)+SO_(4)`
`Zn^(2+)+underset(2mol)(2e^(-)) to underset(1mol)(Zn)=65.4g`
`=2xx96500C`
`=193000C`
193000 C deposit zinc=65.4 g
`therefore 1350` C will deposit zinc
`=((65.4g)xx(1350C))/(193000C)`
=0.457 g