A solution of `CuSO_4` is electrolysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode?

Explanation

`I=1.5A,t=10" min"=10xx60=600s`
`Q=Ixxt=(1.5A)xx(600s)=900C`
`CuSO_(4)hArr Cu^(2+)+SO_(4)^(2-)`
`Cu^(2+)+2e^(-) to underset(1mol)(Cu)`
`=2xx96500`
`=193000C=63.5g`
193000 C of electricity deposit copper
=63.5 g
`therefore` 900 C of electricity will deposit copper
`=(63.5xx900)/(193000)=0.296g`