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A charged particle having a mass of 1.6x...

A charged particle having a mass of `1.6xx10^(-26) kg` comes out of accelerator tube with kinetic energy `2xx10^3 eV` . Calculate the smallest magnitude of the magnetic field that should be applied in vertically downwards direction to just prevent the charged particle from colliding the plate (Assume charge on particle = charge of the proton)

A

2 Tesla

B

4 Tesla

C

0.02 Tesla

D

0.04 Tesla

Text Solution

Verified by Experts

The correct Answer is:
A
`r=d " or " (sqrt(2mk))/(qB)= d rArr B = sqrt((2mk)/(q^(2)d^(2)))`
or `B= sqrt((2xx1.6 xx 10^(-26) xx2xx10^(3)xx e)/(e^(2)xx10^(-4)))`
`B= sqrt((2xx1.6 xx 10^(-26) xx 2xx10^(3))/(1.6 xx 10^(-19) xx 10^(-4)))= 2` Tesla
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