Statement I: `t a n5theta-t a n3theta-t a n2theta=t a n5thetat a n3thetat a n2theta` Statement II: `x=y+z=>t a n x-t a n y-t a n z=t a n x t a n y t a n zdot` a.`A` b. `\ B` c.`\ C` d. `D`

Solve the following equation: t a ntheta+t a n2theta+t a n3theta=0

If costheta=4/5a n d\ theta is acute, find the t a n2theta

If A+B=C , then write the value of t a n A\ t a n B\ t a n Cdot

Statement 1 is True: Statement 2 is True; Statement 2 is a correct explanation for statement 1 Statement 1 is true, Statement 2 is true;2 Statement 2 not a correct explanation for statement 1. Statement 1 is true, statement 2 is false Statement 1 is false, statement 2 is true Statement I: If A is obtuse angle I A B C , then tanB\ t a n C<1 because Statement II: In A B C ,\ t a n A=(t a n B+t a n C)/(t a n B t a n C-1)\ a. A b. \ B c. \ C d. D

If t a n^2theta=1-a^2 , prove that sectheta+t a n^3thetacos e ctheta=(2-a^2)^(3//2).

Prove that: t a n 70^0=t a n 20^0+2t a n 50^0dot

Prove that: t a n 70^0=t a n 20^0+2t a n 50^0dot

Prove that: \ t a n 20^0t a n 30^0t a n 40^0t a n 80^0=1

If x=a\ s e c^3theta and y=a\ t a n^3theta , find (dy)/(dx) at theta=pi/3

Show that: t a n(60^0+theta)t a n(60^0-theta)=(2cos2theta+1)/(2cos2theta-1)