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If alpha is a root of 25 cos^2theta+5cos...

If `alpha` is a root of `25` `cos^2theta+5costheta-12=0`, `pi/2 < alpha < pi,` , then `sin2alpha=`
a. `(24)/(25)`
b. `-(24)/(25)`
c. `(13)/(18)`
d. `-(13)/(18)`

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