Let `P Q R` be a triangle of area `` with `a=2,b=7/2,a n dc=5/2, w h e r ea , b ,a n dc` are the lengths of the sides of the triangle opposite to the angles at `P ,Q ,a n dR` respectively. Then `(2sinP-sin2P)/(2sinP+sin2P)e q u a l s` (a)`3/(4Δ)` (b) `(45)/(4Δ)`(c) `(3/(4Δ))^2` (d) `((45)/(4Δ))^2`

Options

A. `(3)/(4Delta)`
B. `(45)/(4Delta)`
C. `((3)/(4Delta))^(2)`
D. `((45)/(4Delta))^(2)`

Explanation

To solve the given problem step by step, we will follow the outlined approach based on the video transcript.

### Step 1: Write the given expression
We start with the expression we need to evaluate:
\[ \frac{2 \sin P - \sin 2P}{2 \sin P + \sin 2P} \]

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