If `(log)_(10)33. 8=1. 5289 ,\ t h e n(log)_(10)0. 338` is-
a.` 1 .5289` b. `\ -0. 4711` c.`-1. 5289` d. ` 2 .5289`

Given: (log)_(10)34. 56=1. 5386 find (log)_(10)3. 456 and(log)_(10)0. 003456.

Given (log)_(10)34. 56=1. 5386 ,\ find (log)_(10)3. 456 ;(log)_(10)0. 3456\ &(log)_(10)0. 003456

If (log)_e4-1. 3868 ,t h e n(log)_e 4.01= 1.3968 (b) 1.3898 (c) 1.3893 (d) none of these

If x=(log)_k b=(log)_b c=1/2(log)_c d ,t h e n(log)_k d is equal to 6x b. (x^3)/2 c. 2x^3 d. 2x^8

If (log)_e4=1. 3868 , then (log)_e 4.01= (a) 1.3968 (b) 1.3898 (c) 1.3893 (d) none of these

If (log)_a x=p\ a n d(log)_b x^2=q ,\ t h e n(log)_xsqrt(a b) is equal to (where a ,\ b ,\ x in R^+-{1} )- a. 1/p+1/q b. 1/(2p)+1/q c. 1/p+1/(2q) d. 1/(2p)+1/(2q)

If "log"_(e) 2."log"_(x) 27 = "log"_(10) 8."log"_(e) 10 , then x =

(log)_(A E)((A C)/(C D)) is equal to a. sqrt(2) b. \ 1 c. \ 0 d. -1

If (log)_(10)2=a ,(log)_(10)3=bt h e n(log)_(0. 72)(9. 6) in terms of a and b is equal to (a) (2a+3b-1)/(5a+b-2) (b) (5a+b-1)/(3a+2b-2) (c) (3a+b-2)/(2a+3b-1) (d) (2a+5b-2)/(3a+b-1)

Comprehension 3 If P is the non negative characteristic of (log)_(10)N , the number of significant digit in N\ i s\ P+1 . If P is the negative characteristic of (log)_(10)N , then number of zeros after decimal before a significant digit start are P-1.( Use log_(10)\ 2=0. 301.(log)_(10)3=0. 4771 ) Number of significant digit in N , where N=(5/3)^(100), is- a. 23 b. \ 22 c. \ 21 d. none