A sample of `MgSO_(4)` has `6.023 xx 10^(20)O` atoms What is mass of `Mg` in sample ? .

Explanation

To solve the problem of finding the mass of magnesium (Mg) in a sample of magnesium sulfate (MgSO₄) that contains \(6.023 \times 10^{20}\) oxygen (O) atoms, we can follow these steps:

### Step 1: Determine the number of moles of oxygen atoms
We know that 1 mole of any substance contains \(6.022 \times 10^{23}\) entities (atoms, molecules, etc.). Thus, we can calculate the number of moles of oxygen atoms in the sample:

\[ \text{Number of moles of O} = \frac{6.023 \times 10^{20}}{6.022 \times 10^{23}} = \frac{6.023}{6.022} \times 10^{-3} \approx 1 \times 10^{-3} \text{ moles of O} \]
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