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If 2.4gm Mg is treated with 0.64 gm O(2)...

If `2.4gm` Mg is treated with `0.64 gm O_(2)` Find composition of final product mixture ?
[Atomic Mass `Mg = 24]` .

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To solve the problem of determining the composition of the final product mixture when `2.4 g` of magnesium (Mg) is treated with `0.64 g` of oxygen (O₂), we can follow these steps: ### Step 1: Calculate the number of moles of magnesium (Mg) and oxygen (O₂). 1. **For Magnesium (Mg)**: - Atomic mass of Mg = 24 g/mol - Moles of Mg = mass (g) / molar mass (g/mol) = 2.4 g / 24 g/mol = 0.1 moles ...
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