`27.6gK_(2)CO_(3)` was treated by a series of reagents so as to convent all of its carbon to `K_(2)Zn_(3)[Fe(CN)_(6)]_(2)` Calculate the weight of the product [mol.wt. of `K_(2)CO_(3)=138` and mol. Wt. of `K_(2)Zn_(3)[Fe(CN)_(6)]_(2)=698]` .

Explanation

To solve the problem, we will follow these steps:

### Step 1: Determine the number of moles of K₂CO₃
We start by calculating the number of moles of K₂CO₃ using the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
Given:
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