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0.15g of substance displaced 58.9cm^(3) ...

`0.15g` of substance displaced `58.9cm^(3)` of air at `300K` and `746mm` pressure Calculate the molecular mass `("Aq Tension at" 300K = 26.7mm)` .

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To calculate the molecular mass of the substance, we will use the ideal gas equation and the given data. Here’s a step-by-step solution: ### Step 1: Identify the given data - Mass of the substance (W) = 0.15 g - Volume of air displaced (V) = 58.9 cm³ = 58.9 × 10⁻³ L = 0.0589 L - Temperature (T) = 300 K - Total pressure (P) = 746 mmHg - Aqueous tension at 300 K = 26.7 mmHg ...
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