Home
Class 11
CHEMISTRY
Find final molarity in each case : (i) 5...

Find final molarity in each case : (i) 500ml 0.1M HCl + 500ml 0.2M HCl (ii)50ml 0.1M HCl + 150ml 0.3M HCl+ 300ml H2O (iii) 4.9g H2SO4 + 250ml H2O + 250ml 0.1M H2SO4

Text Solution

AI Generated Solution

To find the final molarity in each case, we will use the formula for molarity, which is: \[ \text{Molarity (M)} = \frac{\text{Total number of moles}}{\text{Total volume in liters}} \] We will calculate the total number of moles for each case and then divide by the total volume in liters. ...
Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT

    ALLEN|Exercise EXERCISE - 01|49 Videos

  • MOLE CONCEPT

    ALLEN|Exercise EXERCISE - 02|46 Videos

  • IUPAC NOMENCLATURE

    ALLEN|Exercise Exercise - 05(B)|7 Videos

  • QUANTUM NUMBER & PERIODIC TABLE

    ALLEN|Exercise J-ADVANCED EXERCISE|24 Videos

Similar Questions

Explore conceptually related problems

Find final molarity in each case : (i) 400 mL 0.1 M HCl+ 400 ml 0.2 M HCl

Find the resultant molarity obtained by mixing the following (i) 2 litre, 0.5 M HCl + 3 litre, 0.2 M HCl (ii) 2 litre, 0.2 M HCl + 500 ml, 0.4 M HCl

Which will make basic buffer? a) 100 m L o f 0.1 M HCl + 200 mL of 0.1 M N H 4 O H b) 100 mL of 0.1 M HCl + 100 mL of 0.1 M NaOH c) 50 mL of 0.1 M NaOH +25 mL of 0.1 M C H 3 C O O H d) 100 mL of 0.1 M C H 3 C O O H + 100 mL of 0.1 M NaOH.

The final molarity of a solution made by mixing 50 mL of 0.5 M HCl, 150 mL of 0.25 M HCl and water to make the volume 250 mL is

Calculate the pH of the resulting solution formed by mixing the following solutions: (a) 20ml" of "0.2M" "Ba(OH)_(2)+30mL" of "0.1M" "HCl (b) 2 mL" of "0.1" M "HCl + 10 ml" of "0.01" M "KOH (c ) 10mL" of "0.1" M "H_(2)SO_(4)+10 mL" of "0.1 M KOH .

Calculate the pH of the following mixtures given (pK_(a) = pK_(b) = 4.7447) : a. 50mL 0.1 M NaOH +50mL 0.1MCH_(3)COOH b. 50mL 0.1 m NaOH +50mL 0.05 M CH_(3)COOH c. 50mL 0.05M NaOH +50mL 0.1 M CH_(3)COOH d. 50mL 0.1M NH_(4)OH +50mL 0.05 MHCI e. 50mL 0.05M NH_(4)OH +50mL 0.1 MHCI f. 50mL 0.05 M NH_(4)OH + 50mL 0.05 M CH_(3)COOH

The resulting solution obtained by mixing 100ml, 0.1M H_2SO_4 and 50ml ,0.4M NaOH will be

100 ml of 0.1 M HCl and 100 ml of 0.1 M HOCN are mixed then (K_a= 1.2 xx 10^(-6))

Following solutions were prepared by mixing different volumes of NaOH and HCI of different concentrations: (i) 60 mL M/10 HCl + 40 mL M/10 NaOH (ii) 55 mL M/10 HCl + 45 mL M/10 NaOH , (iii) 75 mL M/5 HCl + 25 mL M/5 NaOH (iv) 100 mL M/10 HCl + 100 mL M/10 NaOH pH of which one of them will be equal to 1?

The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M) HCl will be: