Find molality of aqueous solution of `CH_(3)COOH` whose molarity is `2M` and density `d = 1.2g//mL`
`"Hint":m=(M)/(d-MM_(s))xx1000`
Where d = density in `gL^(-1)`, ,M = Molartity, m = molality, `M_(S) =` molar mass of solute .

Explanation

To find the molality of an aqueous solution of acetic acid (CH₃COOH) with a given molarity and density, we can follow these steps:

### Step 1: Identify the given values
- Molarity (M) = 2 M
- Density (d) = 1.2 g/mL
- Molar mass of acetic acid (CH₃COOH) = 60 g/mol

### Step 2: Convert density to g/L
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