A solution is made by mixing `300ml 1.5M Al_(2) (SO_(4))_(3) + 300ml 2M CaSO_(4) + 400ml 3.5M CaCl_(2)`
Find final molarity of `(1) SO_(4).^(-2), (2) Ca^(2+)` (3) `Cl^(-)` [Assume complete dissociation of these compound] .

Explanation

To find the final molarity of the ions \( SO_4^{2-} \), \( Ca^{2+} \), and \( Cl^{-} \) in the mixed solution, we will follow these steps:

### Step 1: Calculate the total moles of \( SO_4^{2-} \)

1. **Identify the sources of \( SO_4^{2-} \)**:
- From \( Al_2(SO_4)_3 \): Each mole of \( Al_2(SO_4)_3 \) produces 3 moles of \( SO_4^{2-} \).
- From \( CaSO_4 \): Each mole of \( CaSO_4 \) produces 1 mole of \( SO_4^{2-} \).

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