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An alpha-particle having K.E. =7.7MeV is...

An `alpha`-particle having `K.E. =7.7MeV` is scattered by gold `(z=79)` nucleus through `180^(@)` Find distance of closet approach.

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To find the distance of closest approach of an alpha particle scattered by a gold nucleus, we can use the relationship between kinetic energy and electrostatic potential energy. The formula we will use is derived from the conservation of energy principle. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Kinetic Energy (K.E) of the alpha particle = 7.7 MeV - Atomic number (Z) of gold = 79 ...
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