Home
Class 11
CHEMISTRY
In Balmer series of H atom spectrum, whi...

In Balmer series of `H` atom spectrum, which electronic transitions represents `3^(rd)` line?

Text Solution

AI Generated Solution

To determine which electronic transition represents the third line in the Balmer series of the hydrogen atom spectrum, we can follow these steps: ### Step 1: Understand the Balmer Series The Balmer series corresponds to electronic transitions in a hydrogen atom where an electron falls from a higher energy level (n1) to the second energy level (n2 = 2). The lines in the Balmer series are numbered based on the transitions from higher levels to n2. ### Step 2: Identify the Transition Levels The first line in the Balmer series corresponds to the transition from n1 = 3 to n2 = 2. The second line corresponds to the transition from n1 = 4 to n2 = 2. Therefore, the third line corresponds to the transition from n1 = 5 to n2 = 2. ...
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    ALLEN|Exercise Exercise - 01|38 Videos

  • ATOMIC STRUCTURE

    ALLEN|Exercise Exercise - 02|59 Videos

  • IUPAC NOMENCLATURE

    ALLEN|Exercise Exercise - 05(B)|7 Videos

Similar Questions

Explore conceptually related problems

One of the lines in the emission spectrum of Li^(2 +) has the same wavelength as that of the second line of Balmer series in hydrogen spectrum. The electronic transition correspnding to this line is.

The third in Balmer series corresponds to an electronic transition between which Bohr's orbits in hydrogen

Balmer series lies in which region of electromagnetic spectrum

Balmer series lies in which region of electromagnetic spectrum

In Balmer series of lines of hydrogen spectrum, the third line from the red end corresponds to which one of the following inner-orbit jumps of the electron for Bohr orbits in an atom of hydrogen?

The balmer series for the H-atom can be ob-served

The balmer series for the H-atom can be ob-served

In balmer series of emission spectrum of hydrogen, first four lines with different wavelength H_alpha , H_beta , H_gamma and H_delta are obtained. Which line has maximum frequency out of these ?

The Balmer series in the hydrogen spectrum corresponds to the transition from n_(1)=2 to n_(2)=3,4 ........ This series lies in the visible region. Calculate the wave number of line associated with the transition in Balmer series when the electron moves to n=4 orbit. (R_(H)=109677cm^(-1))

In the spectrum of singly ionized helium , the wavelength of a line abserved is almost the same as the first line of Balmer series of hydrogen . It is due to transition of electron from n_(1) = 6 to n_(2) = ^(''**'') . What is the value of (''**'') .