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Consider psi (wave function) of 2s atomi...

Consider `psi` (wave function) of `2s` atomic orbital of H-atom is-
`psi_(2s)=(1)/(4sqrt(2pia_(0)^(3//2)))[2-(r )/(a_(0))]e^.(r )/(2a_(0)`
Find distance of radial node from nucleous in terms of `a_(0)`

A

`r=a_(0)`

B

`r=2a_(0)`

C

`r=a_(0)`

D

data insufficient

Text Solution

AI Generated Solution

To find the distance of the radial node from the nucleus in terms of \( a_0 \) for the given wave function of the 2s atomic orbital of the hydrogen atom, we can follow these steps: ### Step 1: Understand the wave function The wave function for the 2s atomic orbital is given by: \[ \psi_{2s} = \frac{1}{4\sqrt{2\pi a_0^{3/2}}} \left( 2 - \frac{r}{a_0} \right) e^{-\frac{r}{2a_0}} \] We need to find the radial nodes, which occur when the radial part of the wave function equals zero. ...
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