What is the angular momentum of an electron in `3P` orbital.

Answer

To find the angular momentum of an electron in the 3P orbital, we can follow these steps:

### Step 1: Identify the Angular Quantum Number (L)
The angular quantum number (L) for an orbital is determined by the type of orbital:
- For s orbitals, L = 0
- For p orbitals, L = 1
- For d orbitals, L = 2
- For f orbitals, L = 3

Since we are dealing with a 3P orbital, we have:
- L = 1

### Step 2: Use the Angular Momentum Formula
The formula for the angular momentum (L) of an electron in an orbital is given by:
\[ L = \sqrt{L(L + 1)} \cdot \frac{h}{2\pi} \]
where:
- \( h \) is Planck's constant.

### Step 3: Substitute the Value of L into the Formula
Now, we can substitute L = 1 into the formula:
\[ L = \sqrt{1(1 + 1)} \cdot \frac{h}{2\pi} \]

### Step 4: Simplify the Expression
Now we simplify the expression:
\[ L = \sqrt{1 \cdot 2} \cdot \frac{h}{2\pi} \]
\[ L = \sqrt{2} \cdot \frac{h}{2\pi} \]

### Step 5: Final Expression for Angular Momentum
Thus, the angular momentum of an electron in the 3P orbital is:
\[ L = \frac{\sqrt{2} \cdot h}{2\pi} \]

### Summary
The angular momentum of an electron in the 3P orbital is given by:
\[ L = \frac{\sqrt{2} \cdot h}{2\pi} \]

---