Home
Class 11
CHEMISTRY
Calculate distance of closet approach by...

Calculate distance of closet approach by an `alpha `-particle of `KE=2.5 MeV` being scattered by gold nucleus `(Z=79)`.

Text Solution

AI Generated Solution

To calculate the distance of closest approach by an alpha particle with a kinetic energy of 2.5 MeV being scattered by a gold nucleus (Z=79), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Concept**: The distance of closest approach (R) can be calculated using the formula derived from the conservation of energy. The kinetic energy (KE) of the alpha particle is converted into electrostatic potential energy at the point of closest approach. 2. **Formula**: The formula to calculate the distance of closest approach is given by: \[ ...
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    ALLEN|Exercise Exercise - 01|38 Videos

  • ATOMIC STRUCTURE

    ALLEN|Exercise Exercise - 02|59 Videos

  • IUPAC NOMENCLATURE

    ALLEN|Exercise Exercise - 05(B)|7 Videos

Similar Questions

Explore conceptually related problems

In a Geiger - Marsden experiment, calculate the distance of closest approach to the nucleus of Z=75, when an alpha - particle of 5 Me V enery impinges on it before it comes momentarily to rest and reverses its direction. How will the distance of closest approach be affected when the kinetic energy of the alpha -particle is doubled ?

What is the distance of closest approach to the nucleus for an alpha -particle of energy 5 MeV which undergoes scattering in the Gieger-Marsden experiment.

In a Geiger- Marsden experiment, calculate the distance of closest approach to the nucleus of Z=80, when an alpha particle of 8 Me V energy impinges on it before it comes momentarily to rest and reverses its direction. How will the distance of closest approach be affected when the kinetic energy of the alpha- particle is doubled ?

Define the distance of closest approach. An alpha -particle of kinetic enegy 'K' is bombarded on a thin gold foil. The distance of the closest approach is 'r' . What will be the distance of closest approach for an alpha -particle of double the kinetic energy ?

(a) Define the distance of closest approach. A alpha -particle of kinetic energy K is bombarded on a thin gld foil. The distance of the closest approach is r_(a) . What will be the distance of closest approach for an alpha -particle of double the kinetic energy ? (b) Show that the radius of the orbit of an electron in hydrogen atoms varies as n^(2) , where n is the principal quantum number of the atom.

The closet distance of approach of an alpha - particle travelling with a velocity V towards a stationary nucles is .d.. For the closet distance to because d/3 towards stationary nucleus of double the charge the velocity of projection of the alpha - particle has to be

In scattering experiment, find the distance of closest approach, if a 6 MeV alpha - particle is used

The distance of closest approach of an alpha -particle fired at nucleus with momentum p is d. The distance of closest approach when the alpha -particle is fired at same nucleus with momentum 3p will be

The distance of closest approach of an alpha-particle fired towards a nucleus with momentum p is r. What will be the distance of closest approach when the momentum of alpha-particle is 2p ?

The diagram shown the path of four alpha -particles of the same energy being scattered by the nucleus of an atom simutaneously. Which of these are/is not physically possible ?