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In a certain electronic transition in t...

In a certain electronic transition in the hydrogen atoms from an initial state `(1)` to a final state `(2)`, the difference in the orbit radius `((r_(1)-r_(2))` is 24 times the first Bohr radius. Identify the transition-

A

`5rarr1`

B

`25rarr1`

C

`8rarr3`

D

`7rarr5`

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The correct Answer is:
To solve the problem of identifying the electronic transition in a hydrogen atom based on the difference in orbit radii, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship Between Radius and Principal Quantum Number**: The radius of the electron orbit in a hydrogen atom is given by the formula: \[ r_n = n^2 \cdot r_0 \] where \( r_0 \) is the first Bohr radius and \( n \) is the principal quantum number. 2. **Set Up the Equation for the Difference in Radii**: We need to find the difference in radii between two states \( n_1 \) and \( n_2 \): \[ r_{n_2} - r_{n_1} = r_0(n_2^2 - n_1^2) \] According to the problem, this difference is equal to \( 24 \cdot r_0 \): \[ r_0(n_2^2 - n_1^2) = 24 \cdot r_0 \] 3. **Simplify the Equation**: We can divide both sides by \( r_0 \) (since \( r_0 \neq 0 \)): \[ n_2^2 - n_1^2 = 24 \] 4. **Factor the Difference of Squares**: The equation \( n_2^2 - n_1^2 = 24 \) can be factored as: \[ (n_2 - n_1)(n_2 + n_1) = 24 \] 5. **Identify Possible Values for \( n_1 \) and \( n_2 \)**: We need to find pairs of integers \( (n_1, n_2) \) such that their product equals 24. The factor pairs of 24 are: - \( (1, 24) \) - \( (2, 12) \) - \( (3, 8) \) - \( (4, 6) \) We can set \( n_2 - n_1 = a \) and \( n_2 + n_1 = b \), where \( a \cdot b = 24 \). 6. **Solve for Each Pair**: For each factor pair \( (a, b) \): - \( n_2 = \frac{a + b}{2} \) - \( n_1 = \frac{b - a}{2} \) Let's evaluate the pairs: - For \( (4, 6) \): - \( n_2 - n_1 = 4 \) - \( n_2 + n_1 = 6 \) - Solving gives \( n_2 = 5 \) and \( n_1 = 1 \). - For \( (3, 8) \): - \( n_2 - n_1 = 3 \) - \( n_2 + n_1 = 8 \) - Solving gives \( n_2 = 7 \) and \( n_1 = 5 \). 7. **Conclusion**: The possible transitions are: - From \( n_1 = 1 \) to \( n_2 = 5 \) - From \( n_1 = 5 \) to \( n_2 = 7 \) ### Final Answer: The transitions identified are \( (1 \to 5) \) and \( (5 \to 7) \).

To solve the problem of identifying the electronic transition in a hydrogen atom based on the difference in orbit radii, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship Between Radius and Principal Quantum Number**: The radius of the electron orbit in a hydrogen atom is given by the formula: \[ r_n = n^2 \cdot r_0 ...
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ALLEN-ATOMIC STRUCTURE-Exercise - 01
  1. If the value of E=-78.4 "kcal//mol", the order of the orbit in hydroge...

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  2. If velocity of an electron in 1st orbit of H atoms is V , what will b...

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  3. In a certain electronic transition in the hydrogen atoms from an init...

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  4. Match the following - {:((a),"Energy of ground state of" He^(+),(i)...

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  5. The energy of hydrogen atom in its ground state is -13.6 eV. The ener...

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  6. Total no of lines in Lyman series of H spectrum will be- (where n=n...

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  7. The spectrum of He is expected to be similar to.

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  8. What possibly can be the ratio of the de Broglie wavelength for two el...

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  9. The uncertainty in momentum of an electron is 1 xx 10^-5 kg - m//s. Th...

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  10. An alpha-"particle" is accelerated through a potential difference of V...

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  11. The orbital with zero orbital angular momentum is.

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  12. Which of the following is electronic configuration of Cu^(2+) (Z = 29)...

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  13. The electronic configuration of the Mn^(4+) ion is -

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  14. Which of the following has the maximum number of unpaired d-electron?

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  15. The total spin resulting from a d^7 configuration is :

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  16. {:("Given",K,L,M,N,),(,2,8,11,2,):} The number of electrons present ...

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  17. The configuration is 1s^(2) 2s^(2) 2p^(5) 3s^(1) shows :

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  18. The possible value of l and m for the last electron in the Cl^(- )ion ...

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  19. In which transition, one quantum of energy is emitted -

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  20. Chose the currect on the basis of Bohr's theory

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