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Give the correct order of initials T (tr...

Give the correct order of initials `T` (true) or `F` (false) for following statements :-
(I) If an ion has `2` electrons in `K` shell, `8` electrons in `I`. Shell and `6` electrons in `M` shell, then number of `S` electrons present in that element is `6`.
(II) The maximum number of electrons in a subshell is given by `2n^(2)`
(III) If electron has magnetic quantum number `-1`, then it cannot be present in s-orbital.
(IV) Only one radial node is present in `3p` orbital.

A

`"TTFF"`

B

`"FFTF"`

C

TFTT

D

`FFTF`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of initials `T` (true) or `F` (false) for the given statements, we will analyze each statement one by one. ### Step-by-Step Solution: **Statement I:** If an ion has `2` electrons in `K` shell, `8` electrons in `L` shell, and `6` electrons in `M` shell, then the number of `S` electrons present in that element is `6`. 1. **Analysis of Electron Configuration:** - The `K` shell can hold a maximum of `2` electrons (1s). - The `L` shell can hold a maximum of `8` electrons (2s and 2p). - The `M` shell can hold a maximum of `18` electrons (3s, 3p, and 3d). - The total number of electrons in the `K`, `L`, and `M` shells is `2 + 8 + 6 = 16`. 2. **Determining the Number of `S` Electrons:** - In the `K` shell, there is `1` s orbital (2 electrons). - In the `L` shell, there is `1` s orbital (2 electrons). - In the `M` shell, there is `1` s orbital (2 electrons). - Thus, the total number of `s` electrons = `2 (from K) + 2 (from L) + 2 (from M) = 6`. **Conclusion for Statement I:** True (T). --- **Statement II:** The maximum number of electrons in a subshell is given by `2n^2`. 1. **Understanding the Formula:** - The formula `2n^2` gives the maximum number of electrons in a shell, not a subshell. - For subshells, the maximum number of electrons is given by `2(2l + 1)` where `l` is the azimuthal quantum number. **Conclusion for Statement II:** False (F). --- **Statement III:** If an electron has a magnetic quantum number `-1`, then it cannot be present in an s-orbital. 1. **Understanding Quantum Numbers:** - The magnetic quantum number (`m_l`) can take values from `-l` to `+l`. - For `s` orbitals, `l = 0`, thus `m_l` can only be `0`. - If `m_l = -1`, then `l` must be `1`, which corresponds to `p` orbitals. **Conclusion for Statement III:** True (T). --- **Statement IV:** Only one radial node is present in the `3p` orbital. 1. **Calculating Radial Nodes:** - The number of radial nodes is given by the formula `n - l - 1`. - For `3p`, `n = 3` and `l = 1`. - Therefore, the number of radial nodes = `3 - 1 - 1 = 1`. **Conclusion for Statement IV:** True (T). --- ### Final Answers: - Statement I: T - Statement II: F - Statement III: T - Statement IV: T ### Summary of Answers: - I: T - II: F - III: T - IV: T ---

To determine the correct order of initials `T` (true) or `F` (false) for the given statements, we will analyze each statement one by one. ### Step-by-Step Solution: **Statement I:** If an ion has `2` electrons in `K` shell, `8` electrons in `L` shell, and `6` electrons in `M` shell, then the number of `S` electrons present in that element is `6`. 1. **Analysis of Electron Configuration:** - The `K` shell can hold a maximum of `2` electrons (1s). ...
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