If the nitrogen atom has electronic configuration `1s^(7),` it would have energy lower than that of the normal ground state configuration `1s^(2)2s^(2)3p^(3)`, because the electrons would be closer to the nucleus. Yet `1s^(7)` is not observed because it violates.

Options

A. Heisenberg uncertainty principle
B. Hunds rule
C. Pauli's exclusion principle
D. Bohr postulate of stationary orbits

Answer

C

Explanation

For `d_(yz), xy` and `xz` are nodal palne node `=(n-l-1)=6-2-1implies 3`