Consider the following nuclear reactions involving X and Y.
`X rarr Y + ._(2)^(4)He`
`Y rarr ._(8)O^(18) + ._(1)H^(1)`
If both neutrons as well as protons in both the sides are conversed in nuclear reaction then moles of neutrons in 4.6 g on X :

Options

A. `3,2.4N_(A)`
B. `3,2.4`
C. `2,4.6`
D. `3,0.2N_(A)`

Explanation

To solve the problem, we need to determine the number of moles of neutrons in 4.6 grams of the element X, which is sodium (Na) with an atomic mass of 23 g/mol.

### Step-by-Step Solution:

1. **Identify the Element X**:
From the nuclear reactions provided, we can deduce that element X is sodium (Na), which has an atomic number of 11 and an atomic mass of 23.

2. **Calculate the Number of Neutrons in Sodium**:
The number of neutrons (N) in an atom can be calculated using the formula:
\[ N = A - Z \]
where A is the atomic mass, and Z is the atomic number. For sodium:
\[ N = 23 - 11 = 12 \]
Therefore, sodium has 12 neutrons.

3. **Determine the Number of Moles of Sodium in 4.6 g**:
To find the number of moles of sodium in 4.6 g, we use the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
Substituting the values:
\[ \text{Number of moles of Na} = \frac{4.6 \, \text{g}}{23 \, \text{g/mol}} = 0.2 \, \text{moles} \]

4. **Calculate the Number of Moles of Neutrons**:
Since each mole of sodium contains 12 moles of neutrons, the total number of moles of neutrons in 4.6 g of sodium is:
\[ \text{Number of moles of neutrons} = \text{Number of moles of Na} \times 12 \]
\[ \text{Number of moles of neutrons} = 0.2 \, \text{moles} \times 12 = 2.4 \, \text{moles} \]

5. **Final Answer**:
The number of moles of neutrons in 4.6 g of X (sodium) is **2.4 moles**.