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The value of the magnetic moment of a pa...

The value of the magnetic moment of a particular ion is `2.83` Bohr magneton. The ion is :-

A

`Fe^(2+)`

B

`Ni^(2+)`

C

`Mn^(2+)`

D

`Co^(3+)`

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To determine the ion with a magnetic moment of 2.83 Bohr magnetons, we can follow these steps: ### Step 1: Understand the formula for magnetic moment The magnetic moment (μ) of an ion can be calculated using the formula: \[ \mu = \sqrt{n(n + 2)} \text{ Bohr magneton} \] where \( n \) is the number of unpaired electrons in the ion. ### Step 2: Identify possible ions and their electronic configurations We will consider the following ions and their respective electronic configurations: 1. **Ferrous ion (Fe²⁺)**: Electronic configuration is \( [Ar] 3d^6 \) 2. **Nickel ion (Ni²⁺)**: Electronic configuration is \( [Ar] 3d^8 \) 3. **Manganese ion (Mn²⁺)**: Electronic configuration is \( [Ar] 3d^5 \) 4. **Cobalt ion (Co³⁺)**: Electronic configuration is \( [Ar] 3d^6 \) ### Step 3: Calculate unpaired electrons for each ion 1. **Fe²⁺ (3d⁶)**: - Configuration: \( \uparrow\downarrow \uparrow \uparrow \uparrow \) - Unpaired electrons: 4 2. **Ni²⁺ (3d⁸)**: - Configuration: \( \uparrow\downarrow \uparrow\downarrow \uparrow \uparrow \uparrow \uparrow \) - Unpaired electrons: 2 3. **Mn²⁺ (3d⁵)**: - Configuration: \( \uparrow \uparrow \uparrow \uparrow \uparrow \) - Unpaired electrons: 5 4. **Co³⁺ (3d⁶)**: - Configuration: Similar to Fe²⁺ - Unpaired electrons: 4 ### Step 4: Calculate magnetic moments for each ion 1. **Fe²⁺**: \[ \mu = \sqrt{4(4 + 2)} = \sqrt{24} \approx 4.89 \text{ Bohr magneton} \] 2. **Ni²⁺**: \[ \mu = \sqrt{2(2 + 2)} = \sqrt{8} \approx 2.83 \text{ Bohr magneton} \] 3. **Mn²⁺**: \[ \mu = \sqrt{5(5 + 2)} = \sqrt{35} \approx 5.92 \text{ Bohr magneton} \] 4. **Co³⁺**: \[ \mu = \sqrt{4(4 + 2)} = \sqrt{24} \approx 4.89 \text{ Bohr magneton} \] ### Step 5: Identify the correct ion From the calculations, we find that the only ion with a magnetic moment of approximately 2.83 Bohr magnetons is **Ni²⁺**. ### Conclusion The ion with a magnetic moment of 2.83 Bohr magneton is **Nickel ion (Ni²⁺)**. ---

To determine the ion with a magnetic moment of 2.83 Bohr magnetons, we can follow these steps: ### Step 1: Understand the formula for magnetic moment The magnetic moment (μ) of an ion can be calculated using the formula: \[ \mu = \sqrt{n(n + 2)} \text{ Bohr magneton} \] where \( n \) is the number of unpaired electrons in the ion. ...
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