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Frequancy =f(1), Time period = T, Energy...

Frequancy `=f_(1)`, Time period = T, Energy of `n^(th)` orbit `= E_(n)`, radius of `n^(th)` orbit `=r^(n)`, Atomic number = Z, Orbit number = n :
`{:(,"Column-I",,"Column-II",),((A),f,(p),n^(3),),((B),T,(q),Z^(2),),((E),E_(n),(r ),(1)/(n^(2)),),((D),(1)/(r_(n)),(s),Z,):}`

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To solve the matching question, we will analyze the relationships between the terms in Column I and Column II based on the principles of atomic structure. ### Step 1: Analyze Frequency (f) The frequency \( f \) is related to the time period \( T \) and can be expressed as: \[ f \propto \frac{1}{T} \] From the relationship of time period, we know: \[ T \propto \frac{n^3}{Z^2} \] Thus, substituting this into the frequency equation: \[ f \propto \frac{Z^2}{n^3} \] This means that frequency \( f \) is proportional to \( Z^2 \) and inversely proportional to \( n^3 \). Therefore, we can match: - \( f \) with \( Z^2 \) (option Q). ### Step 2: Analyze Time Period (T) From the previous analysis, we have: \[ T \propto \frac{n^3}{Z^2} \] This indicates that time period \( T \) is directly proportional to \( n^3 \). Therefore, we can match: - \( T \) with \( n^3 \) (option P). ### Step 3: Analyze Energy of nth Orbit (E_n) The energy \( E_n \) of the nth orbit is given by: \[ E_n \propto \frac{Z^2}{n^2} \] This means that energy \( E_n \) is proportional to \( Z^2 \) and inversely proportional to \( n^2 \). Therefore, we can match: - \( E_n \) with \( Z^2 \) (option Q). ### Step 4: Analyze Radius of nth Orbit (r_n) The radius \( r_n \) of the nth orbit is given by: \[ r_n \propto \frac{n^2}{Z} \] Taking the reciprocal gives: \[ \frac{1}{r_n} \propto \frac{Z}{n^2} \] This means that \( \frac{1}{r_n} \) is proportional to \( Z \) and inversely proportional to \( n^2 \). Therefore, we can match: - \( \frac{1}{r_n} \) with \( Z \) (option S). ### Step 5: Final Matching Now, let's summarize the matches: - \( f \) matches with \( Z^2 \) (Q) - \( T \) matches with \( n^3 \) (P) - \( E_n \) matches with \( Z^2 \) (Q) - \( \frac{1}{r_n} \) matches with \( Z \) (S) ### Final Answers: - A -> Q - B -> P - E -> Q - D -> S
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