Statement-I : Nodal plane of `p_(x)` atmoic orbital is yz plane.
Because
Statement-II : In `p_(x)` atmoic orbital electron density is zero in the yz plane.

Options

A. Statement-I is true, Statement-II is true , Statement-II is correct explanation for Statement-I.
B. Statement-I is true, Statement-II is true , Statement-II is NOT a correct explanation for statement-I
C. Statement-I is true, Statement-II is false
D. Statement-I is false, Statement-II is true

Answer

To analyze the statements provided in the question, we will break down the reasoning step by step.

### Step-by-Step Solution:

1. **Understanding the Statements**:
- **Statement I**: The nodal plane of the `p_x` atomic orbital is the yz plane.
- **Statement II**: In the `p_x` atomic orbital, the electron density is zero in the yz plane.

2. **Analyzing Statement I**:
- The `p_x` atomic orbital is one of the three p orbitals (the others being `p_y` and `p_z`).
- The `p_x` orbital has a specific shape that is oriented along the x-axis.
- The nodal plane is defined as a plane where the probability of finding an electron is zero.

3. **Identifying the Nodal Plane**:
- For the `p_x` orbital, the nodal plane is indeed the yz plane. This is because the `p_x` orbital has lobes extending along the x-axis, and there is no electron density in the yz plane (where x = 0).

4. **Analyzing Statement II**:
- Statement II claims that the electron density in the yz plane is zero for the `p_x` orbital.
- Since the nodal plane is defined as the plane where the probability density is zero, this statement is also correct.

5. **Conclusion**:
- Both statements are correct.
- Furthermore, Statement II correctly explains Statement I because the definition of the nodal plane (where electron density is zero) directly supports the assertion made in Statement I.

### Final Answer:
Both Statement I and Statement II are correct, and Statement II is the correct explanation for Statement I.