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The Schrodinger wave equation for hydrog...

The Schrodinger wave equation for hydrogen atom is
`Psi_(2s)=(1)/(4sqrt(2pi))((1)/(a_(0)))^(3//2)(2-(r)/(a_(0)))e^(-sigma//a_(0))`
where `a_(0)` is Bohr's radius. If the radial node in 2s be at `r_(0)`, then `r_(0)` would be equal to :

Text Solution

Verified by Experts

The correct Answer is:
(a)`r_(0)=2a_(0)" "(b)6.626xx10^(-25)Å`
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