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The kinetic energy of an electron in the...

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_(0)` is Bohr radius] :

A

`(h^(2))/(4pi^(2)ma_(0)^(2))`

B

`(h^(2))/(16pi^(2)ma_(0)^(2))`

C

`(h^(2))/(32pi^(2)ma_(0)^(2))`

D

`(h^(2))/(32pi^(2)ma_(0)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
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