The correct systematic IUPAC name of the given compound is :
`underset(COOH)underset(|)(CH_(2))-underset(COOH)underset(|)overset(OH)overset(|)(C )-CH_(2)-underset(O)underset(||)(C )-OH`

Options

A. 3-Carboxy-3-hydroxy butane dioic acid
B. 2-Hydroxy propane-1,2,3-tricarboxylic acid
C. 3-Hydroxy butane dioic acid
D. 2-Bis(carboxymethyl)-2-hydroxy ethanoic acid

Answer

To determine the correct systematic IUPAC name of the given compound, we will follow the steps outlined below:

### Step 1: Identify the main functional groups
The compound contains three carboxylic acid groups (-COOH) and one hydroxyl group (-OH). According to IUPAC nomenclature rules, carboxylic acids take precedence over alcohols when naming the compound.

### Step 2: Determine the parent chain
We need to identify the longest carbon chain that includes the functional groups. In this case, we will consider a three-carbon chain (propane) as the parent chain because we cannot include all the carboxylic acids in the main chain.

### Step 3: Number the carbon chain
We will number the carbon chain starting from the end closest to the first functional group. In our case, we will number the carbon atoms as follows:
- Carbon 1: First carboxylic acid (-COOH)
- Carbon 2: Hydroxyl group (-OH)
- Carbon 3: Second carboxylic acid (-COOH)

### Step 4: Identify and name the substituents
- At position 2, we have a hydroxyl group, which we will denote as "2-hydroxy".
- At positions 1, 2, and 3, we have three carboxylic acid groups. We denote this as "tricarboxylic acid".

### Step 5: Combine the names
Now we combine the names of the substituents with the name of the parent chain. The complete name will be:
- "2-hydroxypropane-1,2,3-tricarboxylic acid".

### Final Answer
The correct systematic IUPAC name of the given compound is **2-hydroxypropane-1,2,3-tricarboxylic acid**.

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