A compound with molecular formula `C_(8)H_(14)`, contains 12 secondary and two tertiary H atoms. The compound is :

Options

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Answer

To solve the problem of identifying the compound with the molecular formula \( C_8H_{14} \) that contains 12 secondary and 2 tertiary hydrogen atoms, we can follow these steps:

### Step 1: Understand the Definitions
- **Secondary Hydrogen Atoms**: These are hydrogen atoms attached to secondary carbon atoms. A secondary carbon is one that is bonded to two other carbon atoms.
- **Tertiary Hydrogen Atoms**: These are hydrogen atoms attached to tertiary carbon atoms. A tertiary carbon is one that is bonded to three other carbon atoms.

### Step 2: Analyze the Molecular Formula
The molecular formula \( C_8H_{14} \) indicates that the compound is likely an alkene or a cycloalkane due to the number of hydrogens being less than that of a saturated hydrocarbon (which would have \( C_nH_{2n+2} \) hydrogens).

### Step 3: Determine the Structure
Given that there are 12 secondary hydrogens and 2 tertiary hydrogens, we need to visualize or draw possible structures that fit this description.

1. **Count the Carbons**: Start with 8 carbon atoms.
2. **Identify Possible Structures**:
- The structure must have enough secondary and tertiary carbons to account for the given hydrogen counts.

### Step 4: Construct Possible Structures
1. **Tertiary Carbons**: To have 2 tertiary hydrogens, we need 2 tertiary carbons. Each tertiary carbon contributes 3 hydrogen atoms.
2. **Secondary Carbons**: The remaining carbons must be secondary to account for the 12 secondary hydrogens.

### Step 5: Verify the Count
- If we assume a structure with 2 tertiary carbons, we can have:
- 2 tertiary carbons contributing \( 2 \times 3 = 6 \) hydrogen atoms.
- The remaining 6 carbons must be secondary, contributing \( 6 \times 2 = 12 \) hydrogen atoms.

This matches the requirement of 12 secondary and 2 tertiary hydrogen atoms.

### Step 6: Identify the Compound
After constructing and verifying the structure, we find that the compound is likely **2,3-dimethyl-2-pentene** or a similar structure that fits the criteria.

### Conclusion
The compound with the molecular formula \( C_8H_{14} \) that contains 12 secondary and 2 tertiary hydrogen atoms is **2,3-dimethyl-2-pentene**.