The product in the following reaction is:
`Ph-Cl +Fe//Br_(2)rarr` Product

Options

A. o-bromo-chloro benzene
B. p-bromo-chloro benzene
C. A and B both
D. 2,4,6-tribromo chloro benzene

Explanation

To determine the product of the reaction between chlorobenzene (Ph-Cl) and bromine (Br2) in the presence of iron (Fe), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Chlorobenzene (Ph-Cl)
- Bromine (Br2)
- Iron (Fe) as a catalyst

### Step 2: Understand the Reaction Type
This reaction is an electrophilic aromatic substitution. In this type of reaction, the bromine (Br2) will substitute for the chlorine (Cl) on the benzene ring of chlorobenzene.

### Step 3: Analyze the Reactivity
Bromine (Br2) is a strong electrophile, especially in the presence of iron, which can help generate bromine radicals or bromonium ions that can react with the aromatic ring.

### Step 4: Determine the Substitution Positions
Chlorobenzene has a chlorine atom attached to the benzene ring. The presence of the chlorine atom is a deactivating group but also ortho/para directing. This means that bromine will preferentially substitute at the ortho (2-position) and para (4-position) positions relative to the chlorine atom.

### Step 5: Predict the Product
Since bromine can substitute at multiple positions, we can expect multiple bromine atoms to be added to the benzene ring. The most likely product will be:
- Bromine substituting at the 2, 4, and 6 positions of the benzene ring.

Thus, the product will be:
- 2,4,6-tribromochlorobenzene

### Step 6: Write the Final Product
The final product of the reaction is:
- **2,4,6-tribromochlorobenzene**

### Summary
The product of the reaction between chlorobenzene and bromine in the presence of iron is 2,4,6-tribromochlorobenzene.

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