The `0.1M` copper sulphate solution in which copper electrode is dipped at `25^(@)C`. Calculate the electrode potential of copper electrode.
[Given : `E^(0) Cu^(+2)//Cu = 0.34V]`

Explanation

To calculate the electrode potential of the copper electrode in a 0.1 M copper sulfate solution at 25°C, we will use the Nernst equation. The standard electrode potential for the copper half-reaction is given as \( E^\circ_{Cu^{2+}/Cu} = 0.34 \, V \).

### Step-by-Step Solution:

1. **Identify the half-reaction**:
The half-reaction for the reduction of copper ions is:
\[
Cu^{2+} + 2e^- \rightarrow Cu(s)
...